Respuesta :
Answer:
( 6, pi/6)
Step-by-step explanation:
( 3 sqrt(3), 3)
To get r we use x^2 + y ^2 = r^2
( 3 sqrt(3) )^2 + 3^2 = r^2
9 *3 +9 = r^2
27+9 = r^2
36 = r^2
Taking the square root of each side
sqrt(36) = sqrt(r^2)
6 =r
Now we need to find theta
tan theta = y/x
tan theta = 3 / 3 sqrt(3)
tan theta = 1/ sqrt(3)
Taking the inverse tan of each side
tan ^-1 ( tan theta) = tan ^ -1 ( 1/ sqrt(3))
theta = pi /6
r=sqrt(x^2 + y^2)= sqrt(36)= 6
tan(theta)=y/x= sqrt(3)/3
theta = arctan(sqrt(3)/3)= pi/6
So D) (6, pi/6)
tan(theta)=y/x= sqrt(3)/3
theta = arctan(sqrt(3)/3)= pi/6
So D) (6, pi/6)