Question

What is the pH of a solution that has [OH-] = 4.0 x 10-'M?

Answer 1

Answer: 13.60

Explanation:

$\frac{10^{-14} }{4.0 x 10^{-} }$ = 2.5 x10^-14  this =$[H_{3} O^{+} ]$

pH = -log$[H_{3}O^{+} ]$

pH= -log( 2.5 x10^-14) = 13.60

Answer 2

The answer is 13.60! I hope this helps