Question

in a uniform electric field ,the magnitude of the force on a charge of 0.2 coulomb is 10 Newton. Calculate the field intensity​

Answer 1

Answer:

Field intensity​ (E) = 50 newton / coulomb

Explanation:

Given:

Force apply (f) = 10 Newton

Electric charge (q) = 0.2 Coulomb

Find:

Field intensity​ (E)

Computation:

Field intensity​ (E) = Force apply (f) / Electric charge (q)

Field intensity​ (E) = 10 / 0.2

Field intensity​ (E) = 50 newton / coulomb