Respuesta :
Answer:
469.24
Step-by-step explanation:
you have two angles and a side so you can use sine rule to get another side preferrably WY
38/sin40=WY/sin113
WY=54.4
(113 is from subtracting present angles from 180)
using an alternative formula for area which is
[tex]1 \div 2 \: a \: b \: \sin(c) [/tex]
1/2×54.4×38×sin27
(in this formula the angle has to be enclosed by both sides)
Answer
469.42~ ft^2
Explanation
The area of a triangle can be obtained using a formula
1/2absinC
Angle C being YXW is the easiest to work with for reasons revealed later (when using sine rule)
To obtain this angle:
180 - 40 - 27 = 113
Now, you have to use the Sine Rule
Side a/sin (angle A) = Side b/sin (angle B) (or inverse)
38/sin40 = side b/sin 27
Side b = 38/sin40 • sin27
Side b = 26.84~ ft
Since you now have side b and side a as well as angle C (worked out earlier, you can use the formula
1/2absinC
1/2 • 38 • 26.84 • sin(113)
= 469.42~ ft^2
469.42~ ft^2
Explanation
The area of a triangle can be obtained using a formula
1/2absinC
Angle C being YXW is the easiest to work with for reasons revealed later (when using sine rule)
To obtain this angle:
180 - 40 - 27 = 113
Now, you have to use the Sine Rule
Side a/sin (angle A) = Side b/sin (angle B) (or inverse)
38/sin40 = side b/sin 27
Side b = 38/sin40 • sin27
Side b = 26.84~ ft
Since you now have side b and side a as well as angle C (worked out earlier, you can use the formula
1/2absinC
1/2 • 38 • 26.84 • sin(113)
= 469.42~ ft^2