Question

When iron rusts in air, iron(III) oxide is produced.
How many moles of oxygen react with 78.4 mol
of iron in the rusting reaction?
4Fe(s) + 302(g) – 2Fe2O3(s)
Select one:
O a. 58.8
O b. 105
O c. 78.4
O d. 118

Answer 1

A 58.8
If you divide 78.4 by 4 and multiple it by 3, you get 58.8 moles.