Question

What is the sum of arithmetic series 19+25+31+37+… Where n=9 ?

Answer 1

Answer:

387

Step-by-step explanation:

Answer 2

The required sum of the arithmetic series 19+25+31+37+… Where n=9 is 387.

An arithmetic series is given,19+25+31+37+… sum of this series is to be determined where n=9.

What is arithmetic progression?

Arithmetic progression is the series of numbers that have a common difference between adjacent values.

Here,
The Sum of an arithmetic series is given as
$Sn=n/2(2a+(n-1)d)$
Where n (total terms) =9
            a  (first term) = 19
             d (common difference) = 6
Now,
$S_9=9/2(2*19+(9-8)6)\\ S_9=9/2(38+64)\\S_9=9/2*86\\S_9=387$

Thus, the required sum of the arithmetic series 19+25+31+37+… Where n=9 is 387.

Learn more about arithmetic progression here: https://brainly.com/question/20334860

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