Question

Dilate the figure by a scale factor of 0.5 with the origin as the center of dilation. What are the vertices of the image?
1 F '(3, 2.5), G '(5, 0.5), H '(2, 1)
2 F '(2.5, 3), G '(0.5, 5), H '(0.5, 1)
3 F '(−3, −2.5), G '(−5, −0.5), H '(−1, −0.5)
4 F '(3, 2.5), G '(5, 0.5), H '(1, 0.5)

Answer 1

Answer:

4. F '(3, 2.5), G '(5, 0.5), H '(1, 0.5)

Step-by-step explanation:

The formula for dilations are

$\left(x_{1}\cdot t_{1},\ y_{1}\cdot t_{1}\right)$ where t1 is the scale factor

F has coordinates (6,5) so you can write

$(6*0.5,5*0.5)$

Multiply 6 by 0.5 and 5 by 0.5 to get

$(3,2.5)$

Next, do G. It has coordinates (10, 1) so you can write

$(10*0.5, 1*0.5)$

Multiply 10 by 0.5 and 1 by 0.5 to get

$(5, 0.5)$

Finally, point H has coordinates (2, 1) so you can write

$(2*0.5, 1*0.5)$

Multiply 2 by 0.5 and 1 by 0.5 to get

$(1, 0.5)$

Hope this helps. Feel free to ask any follow-up questions.

Have a great day! :)

Answer 2

Answer:  F '(3, 2.5), G '(5, 0.5), H '(1, 0.5).

From the image the vertices are F(6, 5), G(10, 1), H(2, 1).

We have to dilate the figure by a scale factor of 0.5 with the origin as the center of dilation.

We will multiply the vertices by 0.5.

So the new vertices will be: F '(3, 2.5), G '(5, 0.5), H '(1, 0.5).

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