Answer:
The correct options are;
g(x) = -0.27·x² + x + 5
h(x) = 2·㏒(x + 1) + 5
Step-by-step explanation:
To answer the question, we substitute x = 1.9 seconds into the given options as follows;
1) For f(x) = √(1.6·x) + 5
When x = 1.9 seconds, we have;
y = f(1.9) = √(1.6×1.9) + 5 = 6.74 which is not equal to the given height of 5.9 meters
Therefore, f(x) = √(1.6·x) + 5 does not model the height of the drone y as a function of time, x
2) For g(x) = -0.27·x² + x + 5
When x = 1.9 seconds, we have;
y = g(1.9) = -0.27×1.9^2 + 1.9 + 5 = 5.93 meters, which is approximately 5.9 meters to one place of decimal
Therefore, the function, g(x) = -0.27·x² + x + 5, approximately models the height of the drone y as a function of time, x
3) For h(x) = 2·㏒(x + 1) + 5
When x = 1.9 seconds, we have;
y = h(1.9) = 2·log(1.9 + 1) + 5 = 5.92 meters,
The function, h(x) = 2·㏒(x + 1) + 5, approximately models the height of the drone y as a function of time, x
4) For j(x) = -∛(-1.4·x - 1) + 5
When x = 1.9 seconds, we have;
y = j(1.9) = -∛(-1.4×1.9 - 1) + 5 = 6.54 meters
The function j(x) = -∛(-1.4·x - 1) + 5 does not model the height of the drone y as a function of time, x
5) For k(x) = -1.2·x³ + 2.6·x² - 0.5·x + 5
When x = 1.9 seconds, we have;
y = k(1.9) = -1.2×1.9^3 + 2.6×1.9^2 - 0.5×1.9 + 5 = 5.21 meters
Therefore, the function, k(x) = -1.2·x³ + 2.6·x² - 0.5·x + 5, does not model the height of the drone y as a function of time, x
