Question

What is a3 if an=64(12)n−1

Answer 1

Answer:

$\huge\boxed{a_3=9,216}$

Step-by-step explanation:

$a_n=64(12)^{n-1}\\\\\text{substitute}\ n=3:\\\\a_3=64(12)^{3-1}=64(12)^2=64(144)=9,216$