Answer:
The number of students that would have a test score between 61 and 71 are 154 students
Step-by-step explanation:
The given information are;
The mean test score, μ = 61
The standard deviation, σ = 10
The sample size, n = 450
The z score is given as follows;
[tex]Z=\dfrac{x-\mu }{\sigma }[/tex]
We therefore have at x = 61,
[tex]Z=\dfrac{61-61 }{10 } = 0[/tex]
P(x > 61) = P(Z > 0) = 1 - 0.5 = 0.5
For x = 71, we have;
[tex]Z=\dfrac{71-61 }{10 } = 1[/tex]
P(x < 71) = P(Z < 1) = 0.84134
The probability that the score will be between 61 and 71 is the difference between the two probabilities, which is 0.84134 - 0.5 = 0.34134
Given that the probability is equivalent to the proportion of the students that would have a test score between 61 and 71, we have;
The number of students that would have a test score between 61 and 71 = 0.34134 × 450 = 153.6 ≈ 154 to the nearest whole number.