Question

What is the length of the line?

Answer 1

Answer:

$\boxed{\sf B. \ \sqrt{61} }$

Step-by-step explanation:

The line can be made into a hypotenuse of a right triangle.

Find the length of the base and the height of the right triangle.

The base (leg) is 6 units.

The height (leg) is 5 units.

Apply Pythagorean theorem.

$\sf c=\sqrt{a^2 +b^2 }$

$\sf c=\sqrt{6^2 +5^2 }$

$\sf c=\sqrt{36+25 }$

$c=\sqrt{61}$

Answer 2

Answer:

$\sqrt{61}$

Option B is the correct option

Step-by-step explanation:

Assuming center of co-ordinate axes at lower left corner at the line. So end points are:

( x1 , y1 ) = ( 0 , 0 ) and ( x2 , y2 ) = ( 6 , 5 )

Distance between two points is given by formula:

D $= \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} }$

$= \sqrt{ {6 - 0)}^{2} + {(5 - 0)}^{2} }$

$= \sqrt{ {6}^{2} + {5}^{2} }$

$= \sqrt{36 + 25}$

$= \sqrt{61}$

Hope this helps..

Best regards!!