Question

Find the point Q along the directed line segement from point R (-3, 3) to point S(6, -3) that divides the segment in the ratio 2:1.

Answer 1

Answer:

Step-by-step explanation:

m : n = 2 : 1

R (-3, 3 )  ;  x1 = -3 & y1 = 3

S(6 , -3)   ; x2 = 6 & y2 = -3

Formula for the point that divides a line m:n = $(\frac{mx_{2}+nx_{1}}{m+n} , \frac{my_{2}+ny_{1}}{m+n})$

$Q(\frac{2*6+1*(-3)}{2+1}, \frac{2*-3 + 1*3}{2+1})\\\\\\Q(\frac{12-3}{3} , \frac{-6+3}{2+1})\\\\\\Q(\frac{9}{3} , \frac{-3}{3})$

=Q(3, -1)