Question

The product of ages of a man 5 years ago and
5 years hence is 600, find his present age.​

Answer 1

Answer:

25

Step-by-step explanation:

let his age be x, then

5 years ago his age was x - 5 and in 5 years will be x + 5 , thus

(x - 5)(x + 5) = 600 ← expand factors using FOIL

x² - 25 = 600 ( add 25 to both sides )

x² = 625 ( take the square root of both sides )

x = $\sqrt{625}$ = 25

Answer 2

Answer:

$\boxed{Age \ of \ man = 25 \ years}$

Step-by-step explanation:

Let the age be x

Then, the given condition is:

(x-5)(x+5) = 600     [ x-5 for age 5 years ago and x+5 for age 5 years after ]

Using Formula $(a+b)(a-b) = a^2-b^2$

$x^2-25 = 600$

Adding 25 to both sides

$x^2 = 600+25$

$x^2 = 625$

Taking sqrt on both sides

$x = 25$ years