Answer:
Option C. 2000 cm³.
Explanation:
We'll begin by calculating the number of mole in 2 g of Mg. This is illustrated below:
Molar mass of Mg = 24 g/mol
Mass of Mg = 2 g
Mole of Mg =?
Mole = mass /Molar mass
Mole of Mg = 2/24
Mole of Mg = 8.33×10¯² mole.
Next, we shall determine the number of mole of H2 produced from the reaction. This is illustrated below:
Mg(s) + 2H^+ (aq) —› Mg^2+(aq) + H2 (g)
From the balanced equation above,
1 mole of Mg reacted to produce 1 mole of H2.
Therefore, 8.33×10¯² mole of Mg will also produce 8.33×10¯² mole of H2.
Finally, we shall determine the volume of H2 produced. This is illustrated below:
1 mole of H2 occupy 24000 cm³ at room temperature and pressure.
Therefore, 8.33×10¯² mole of H2 will occupy = 8.33×10¯² x 24000 ≈ 2000 cm³ at room temperature and pressure.
Therefore, 2000 cm³ of H2 were obtained from the reaction.