Question

It is estimated that 52% of drivers text while driving. How many people should a police officer expect to pull over until she finds a driver NOT texting while driving?

Answer 1

Answer:

2

Step-by-step explanation:

Let

P = percentage of those that text and drive

S = percentage of those that do not text and drive

P + S = 1

S = 1 - P

S = 1 - 0.52

S = 0.48

The expected number would be:

1/0.48 = 2.08

Which is approximately 2.

Therefore the expected number of people the police officer would expect to pull over until she finds a driver not texting is 2.

Answer 2

The number of people should a police officer expect to pull over until she finds a driver NOT texting while driving is; 2 people

Geometric Random Value

A geometric random value is one that gives a discrete time as to the the first success of an event.  

Now, we are told that it is estimated that 52% of drivers text while driving. Thus, the success is a driver that is not texting, and the probability (p) is 0.52.

This means that the expected value of a geometric random variable is expressed as 1/p.  

Therefore, In this question;

geometric random variable = 1/0.52

⇒ 1.923 ≈ 2

Read more about Geometric Random Variable at; https://brainly.com/question/2254460