Question

Given: f(x) = x2 and g(x) = 2x +1, find f(g(x)].
4x² + 4x + 1
4x² + 1
2x²+1

Answer 1

Answer:

$\huge\boxed{f\bigg(g(x)\bigg)=4x^2+4x+1}$

Step-by-step explanation:

$f(x)=x^2;\ g(x)=2x+1\\\\f\bigg(g(x)\bigg)-\text{instead of}\ x\ \text{in}\ f(x)\ \text{put the expression}\ 2x + 1\\\\f\bigg(g(x)\bigg)=f(2x+1)=(2x+1)^2\qquad\text{use}\ (a+b)^2=a^2+2ab+b^2\\\\f\bigg(g(x)\bigg)=(2x)^2+2(2x)(1)+1^2=4x^2+4x+1$

Answer 2

Answer:

4x^2 + 4x + 1 = f(g(x))

Step-by-step explanation:

To create the function f(g(x)), expand (2x + 1)^2:

We get 4x^2 + 4x + 1 = f(g(x))