Question

this is algebra 1 i need help anybody understand?

Answer 1

Answer:

x=3 and y=4

Step-by-step explanation:

solve x-y=-1 to get x:

x−y=−1

x−y+y=−1+y(Add y to both sides)

x=y−1

Substitute y−1 for the x value in x+2y=11:

3y/3=12/3

y=4

Substitute 4 for the y value in x=y−1:

x=y−1

x=4−1

x=3

so y=4, and x=3

Answer 2

Answer:

d. x = 3, y = 4

Step-by-step explanation:

Well in the following system of equations,

$\left \{ {{x-y=-1} \atop {x+2y= 11}} \right.$

We need to single out x or y in either equations,

let's do the first one for x.

x - y = -1

+y to both sides

x = y - 1

Now we plug in y - 1 for x in x + 2y = 11

(y - 1) + 2y = 11

Combine like terms

3y - 1 = 11

+1

3y = 12

Divide 3 by both sides

y = 4

Now we plug in 4 for y in x - y = -1

x - 4 = -1

+4 to both sides

x = 3

(3,4)

Thus,

the answer is d. x = 3, y = 4.

Hope this helps :)