Answer:
Option (3)
Step-by-step explanation:
[tex](x-i\sqrt{3})[/tex] is a factor of a polynomial given in the options, that means a polynomial having factor as [tex](x-i\sqrt{3})[/tex] will be 0 for the value of x = [tex]i\sqrt{3}[/tex].
Option (1),
3x⁴ + 26x² - 9
= [tex]3(i\sqrt{3})^{4}+26(i\sqrt{3})^2-9[/tex] [For x = [tex]i\sqrt{3}[/tex]]
= 3(9i⁴) + 26(3i²) - 9
= 27 - 78 - 9 [Since i² = -1]
= -60
Option (2),
4x⁴- 11x² + 3
= [tex]4(i\sqrt{3})^4-11(i\sqrt{3})^2+3[/tex]
= 4(9i⁴) - 33i² + 3
= 36 + 33 + 3
= 72
Option (3),
4x⁴ + 11x² - 3
= [tex]4(i\sqrt{3})^4+11(i\sqrt{3})^2-3[/tex]
= 4(9i⁴) + 33i² - 3
= 36 - 33 - 3
= 0
Option (4),
[tex]3x^{4}-26x^{2}-9[/tex]
= [tex]3(i\sqrt{3})^4-26(i\sqrt{3})^{2}-9[/tex]
= 3(9i⁴) - 26(3i²) - 9
= 27 + 78 - 9
= 96
Therefore, [tex](x-i\sqrt{3})[/tex] is a factor of option (3).
