a truck is moving with a certain uniform velocity. it is accelerated uniformly by 0.75 m/s^2.after 20 seconds, the velocity becomes 72 km/h. find the initial velocity

Respuesta :

Answer:

[tex]\boxed{V_{i} = 5\ m/s}[/tex]

Explanation:

Given:

Acceleration = a = 0.75 m/s²

Time = t = ?

Final Velocity = [tex]V_{f}[/tex] = 72 km/hr = 20 m/s

Required:

Initial Velocity = [tex]V_{i}[/tex] = ?

Formula:

a = [tex]\frac{V_{f}-V_{i}}{t}[/tex]

Solution:

For  [tex]V_{i}[/tex]  the formula becomes:

[tex]V_{i} = V_{f}-at[/tex]

[tex]V_{i}[/tex]  = 20 - (0.75)(20)

[tex]V_{i}[/tex]  = 20 - 15

[tex]V_{i}[/tex]  = 5 m/s

In Case: If you want it in km/hr:

[tex]V_{i}[/tex]  = 5 * 3.6

[tex]V_{i}[/tex]  = 18 km/hr

Answer:

5 m/s

Explanation:

acceleration = 0.75 m/s²

time = 20 s

final velocity = 72 km/h = 20 m/s

initial velocity = ?

Apply formula for initial velocity.

[tex]u=-at+v[/tex]

[tex]\sf a=acceleration\\t=time\\v=final \: velocity\\u=initial \: velocity[/tex]

Solve for u.

[tex]u=-(0.75)(20)+ 20[/tex]

[tex]u=-15+20[/tex]

[tex]u= 5[/tex]

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