precalculus help! i'm having some trouble with my summer assignment. help would be very appreciated :)))

6.
[tex]y^2\sqrt[8]{8}[/tex]
Step-by-step explanation:
[tex]\sqrt[8]{8*y*y*y*y*y*y*y*y*y*y*y*y*y*y*y*y}[/tex]
Since there are eight y's in two groups we can take them out which turns into
[tex]y^2\sqrt[8]{8}[/tex]
:)
3.
Problem 3:
We are given the following complex number and I'm assuming we want to simplify it:
[tex]\dfrac{5+i}{6+i}[/tex]
Using the complex arithmetic rule (research about this if you're not familiar with it, it's very helpful):
[tex]=\dfrac{(5\times6+1)+(6-5)i}{6^2+1^2}[/tex]
[tex]=\dfrac{31+i}{37}[/tex]
Simplifying gives us:
[tex]=\dfrac{31}{37}+\dfrac{1}{37}i[/tex]
Problem 6:
You seem to have done this problem correctly
[tex]\sqrt[8]{8y^{16}}[/tex]
Expanding gives us:
[tex]=\sqrt[8]{y^{16}}\times\sqrt[8]{8}[/tex]
[tex]=y^2\sqrt[8]{8}[/tex]
This can't be simplified further as the 8th root of 8 gives us an irrational number
Let me know if you need any clarifications or extra help, thanks!