Question

There are two consecutive integers such that the larger is nine more than twice the smaller. What is the larger number?

Answer 1

Answer:

$\boxed{Larger \ Number = -7}$

Step-by-step explanation:

Let the consecutive numbers be x and x+1 (Since they are coming one after another)

So, Given Condition is:

x+1 = 9 + 2(x)

x+1 = 9 +2x

Subtracting -2x to both sides

x+1-2x = 9

-x+1 = 9

Subtracting 1 from both sides

-x = 9-1

-x = 8

=> x = -8

The larger number is:

=> x+1 = -8+1 = -7