Answer:
i) Estimate the value of the population proportion = 0.8
ii) 95% confidence interval for the population proportion
(0.7214 , 0.8784)
iii) Lower bound = 0.7214
upper bound = 0.8784
Step-by-step explanation:
Step(i):-
Given sample size 'n' = 100
Given data he surveys 100 customers and finds that 80 paid at the pump
sample proportion
[tex]p = \frac{x}{n} = \frac{80}{100} = 0.8[/tex]
Step(ii):-
95% confidence interval for the population proportion is determined by
[tex](p^{-} - Z_{\alpha } \sqrt{\frac{p(1-p)}{n} } , p^{-} + Z_{\alpha } \sqrt{\frac{p(1-p)}{n} })[/tex]
Level of significance
∝ =0.05
Z₀.₀₅ = 1.96
[tex](0.8 - 1.96 \sqrt{\frac{0.8 X 0.2)}{100} } , 0.8 + 1.96 \sqrt{\frac{0.8 X 0.2}{100} })[/tex]
On calculation , we get
(0.8 - 0.0784 , 0.8 + 0.0784)
(0.7214 , 0.8784)
Conclusion:-
95% confidence interval for the population proportion
(0.7214 , 0.8784)