Lesson 6.2: applications of linear systems this is holding me back from completing the course. Please help me guys and girls.

Answer:
see explanation
Step-by-step explanation:
When x = 5 then x > 3 , thus
f(5) = - 1
When x = 3 then x ≤ 3 , thus
f(3) = - 2x + 2 = - 2(3) + 2 = - 6 + 2 = - 4
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When x = - 4 then - 4 ≤ x ≤ 1 , thus
f(- 4) = 2
When x = 3 then x > 1 , thus
f(3) = - x + 1 = - 3 + 1 = - 2
Answer:
Step-by-step explanation:
-2x+2 , x≤ 3
f(x)=-1 , x>3
f(5) = -1 since 5 is greater than 3 you have to use the second equation where x>3
f(3)=-2x+3 use the second equation because the value of x is ≤3
f(3)=-6+3=-3
second question:
-x-4 when x<-4
f(x)= 2 when -4≤x≤1
f(x)=-x+1 when x>1
f(-4) use the second equation because x=-4
f(-4)=2
f(3)=-3+1=-2 use the third equation because x>1 and 3 is greater than 1