Answer:
30 ways
Step-by-step explanation:
Given the following :
Number of boys in school (n1) = 5
Number of girls in school (n2) = 3
Total number of team members to be selected = 4
Number of boys required in team(r1) = 2
Number of girls required in team(r2) = 2
How many different teams made up of two girls and two boys could be chosen?
= (2 boys from 5) * (2 girls from 3)
Using combination :
5C2 * 3C2
Recall :
nCr = n! ÷ (n-r)! r!
5C2 = 5! ÷ (5-2)! 2!
5C2 = 5! ÷ 3!2!
5C2 = (5*4) / 2 * 1 = 10ways
3C2 = 3! ÷ (3-2)! 2!
3C2 = 3! ÷ 1!2!
3C2 = (3) / 1 = 3ways
3C2 = 3/1 = 3ways
10 * 3 = 30 ways
