Question

A force of 3300 N is exerted on a piston that has an area of 0.060 m².
What force is exerted on a second piston that has an area of 0.18 m??

Answer 1

Answer:

9,900 N

Explanation:

We know that the pressure in a fluid is transmitted with an equal pressure throughout, hence the formula $pressure_1$ = $pressure_2$. As your know pressure is represented by force over area, so this formula can be rewritten as $force_1/Area_1$ = $force_2/Area_2$ .

3300 N / 0.060 m² = $force_2$ / 0.18 m²

Let's say that $force_2$ = x. Now let us solve for x.

3300 N / 0.060 m² = x / 0.18 m²,

3300 / 0.060 = x / 0.18,

55,000 = x / 0.18,

x = 55,000 $*$ 0.18 = 9,900 N - this is the force exerted on the second piston