Look at triangle ABC
A (4.5)
5
4
3
2
1
B (2.2)
C (4.2)
1
5 -4 -3 -2 -1 0
1
23
4
5
-1
N
-3
-4
5
What is the length of side AB of the triangle?

A) 3
B) 5
C) square root of 6
D) square root of 13

Look at triangle ABC A 45 5 4 3 2 1 B 22 C 42 1 5 4 3 2 1 0 1 23 4 5 1 N 3 4 5 What is the length of side AB of the triangle A 3 B 5 C square root of 6 D square class=

Respuesta :

Answer:

[tex] \sqrt{13} [/tex]

Option D is the correct option.

Step-by-step explanation:

Given,

A ( 4, 5 ) , B ( 2 , 2 ) , C ( 4 , 2 )

Let,

A ( 4 , 5 ) → ( x1 , y1 )

B ( 2 , 2 ) → ( x2 , y2 )

Now, finding the length of AB

Use the distance formula to find the length of AB

[tex] = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } [/tex]

plug the values

[tex] = \sqrt{ {(2 - 4)}^{2} + {(2 - 5)}^{2} } [/tex]

Calculate the difference

[tex] = \sqrt{ {( - 2)}^{2} + {( - 3)}^{2} } [/tex]

Evaluate the power

[tex] = \sqrt{4 + 9} [/tex]

Add the numbers

[tex] = \sqrt{13} [/tex]

Hope this helps..

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