Answer:
[tex]\large \boxed{\sf \ \ A=5, \ \ B=-13 \ \ }[/tex]
Step-by-step explanation:
Hello,
What you did is correct...
[tex](Ax-3)(x-2)=5x^2+Bx+6\\\\\text{*** we develop the left side ***}\\\\Ax^2+(-2A-3)x+6=5x^2+Bx+6[/tex]
... and you found A by identifying the term in [tex]x^2[/tex] to get A = 5, right?
What about the other terms?
We can then identify the like terms:
>>> term in [tex]x^2\\[/tex]
A = 5
>>> term in x
-2A+3=B
>>> constant term
6 = 6
As we know that A=5 it means that B = -2*5-3=-13
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
