Answer:
[tex]-(3x+2)(x+1)[/tex]
Step-by-step explanation:
So we have the polynomial:
[tex]-3x^2-5x-2\\=-(3x^2+5x+2)[/tex]
(I moved the negative to the outside. This is optional, but it makes things cleaner and you will have to do it eventually.)
This is a quadratic. To factor this, we need to find two numbers p and q such that:
[tex]p\cdot q=ac\\p+q=b[/tex]
From there, we can substitute these numbers in for b.
From the quadratic, a=3, b=5, and c=2. We ignore the negative sign.
In other words, ac=6 and b=5.
After guessing and checking, two numbers that work are 3 and 2 since 3(2)=6 ad 3+2=5. We substitute these values in for b. So:
[tex]-(3x^2+5x+2)\\-(3x^2+3x+2x+2)\\=-(3x(x+1)+2(x+1))\\=-(3x+2)(x+1)[/tex]