Respuesta :

Answer:

[tex]-(3x+2)(x+1)[/tex]

Step-by-step explanation:

So we have the polynomial:

[tex]-3x^2-5x-2\\=-(3x^2+5x+2)[/tex]

(I moved the negative to the outside. This is optional, but it makes things cleaner and you will have to do it eventually.)

This is a quadratic. To factor this, we need to find two numbers p and q such that:

[tex]p\cdot q=ac\\p+q=b[/tex]

From there, we can substitute these numbers in for b.

From the quadratic, a=3, b=5, and c=2. We ignore the negative sign.

In other words, ac=6 and b=5.

After guessing and checking, two numbers that work are 3 and 2 since 3(2)=6 ad 3+2=5. We substitute these values in for b. So:

[tex]-(3x^2+5x+2)\\-(3x^2+3x+2x+2)\\=-(3x(x+1)+2(x+1))\\=-(3x+2)(x+1)[/tex]

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