Question

A tank contains 8000 liters of a solution that is 40% acid. How much water should be added to make a solution that is 30% acid?

Answer 1

Answer:

2,666.67 L of water

Step-by-step explanation:

Solve for W:

1) 3200 = 2400 + 0.3w

2) 800 = 0.3w

Divide both sides by 0.3 to get the variable alone

3) (800)/0.3 = (0.3w)/0.3

4) w = 2,666.67 L