Answer:
[tex]\large \boxed{\sf \ \ y=(x+5)^2+5 \ \ }[/tex]
Step-by-step explanation:
Hello, please find my work below.
[tex]y=x^2+10x+30\\\\\text{*** We can notice that ***}\\\\\text{*** } x^2+10x = x^2+2\cdot 5 \cdot x=(x+5)^2-5^2=(x+5)^2-25\\\\y=x^2+10x+30=(x+5)^2-25+30=(x+5)^2+5\\\\[/tex]
a = 1
h = -5
k = 5
Hope this helps.
Do not hesitate if you need further explanation.
Thank you