Question

If d varies directly as T^2 and D equals 192 when t equals 8 find d when T equals 2

Answer 1

Answer:

d = 12

Step-by-step explanation:

$d \alpha T^2 \\d = kT^2.....(1)\\192 =8^2k\\192=64k\\\frac{192}{64} =\frac{64k}{64} \\k = 3\\d =3T^2 = Formula\: connecting\: d \:and\: T\\\\d = 3(2)^2\\d = 3(4)\\d =12$