Respuesta :

Answer:

Whenever  [tex]a\leq 5[/tex].

Step-by-step explanation:

We can play around with some numbers and develop some rules for this equation.

Note that the number 5 and -5 are used here, so let's try using 5 as a.

[tex]|5-5| = 5-5\\|0| = 0\\0 = 0[/tex]

So 5 works. Let's try a random number like 3.

[tex]|3-5| = 5-3\\|-2| = 2\\2 = 2[/tex]

Okay, with this info we know that we might be able to develop one rule that [tex]a<5[/tex]. Just to test, let's try 0, -3, and -5.

[tex]|0-5| = 5-0\\|-5| = 5\\5 = 5[/tex]

Zero works.

[tex]|-3 - 5| = 5-(-3)\\|-8| = 8\\8 = 8[/tex]

-3 works.

[tex]|-5 -5| = 5-(-5)\\|-10| = 10\\10 = 10[/tex]

-5 works. Now, this might stop here making the equation [tex]-5 \geq a \leq 5[/tex], so let's test a number outside of -5 - say -20.

[tex]|-20 - 5| = 5-(-20)\\|-25| = 25\\25 = 25[/tex]

Yes! This works, so a works for this equation as long as [tex]a \leq 5[/tex].

Hope this helped!

It’s 0 I think but I am not sure I might be wrong but oh well
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