Help need ASAP please!

4a. If a school paid $31.25 per calculator, n number of calculators would signify a total cost of $31.25 [tex]*[/tex] n. Similarly if the school bought x number of calculators they paid a total of $31.25 [tex]*[/tex] x.

4b. We know that the school paid $31.25 per calculator, and that they spent $500. To determine the count of calculators we can create an equation that represents the relationship between the total cost, and the number of calculators.

$500 = $31.25 [tex]*[/tex] x, where x = number of calculators,

x = ( About ) 15 calculators

The exact value was 15.87...but as the number of calculators is a whole number ( you can't have part of a calculator ) our solution had to be rounded down to the nearest whole value. After all, we can't have 16 calculators if there are only " 15.87 " present.

Question 5.

1 ) Kiran won 2 / 3rds as many chips as Jada, so we can say K = [tex]\frac{2}{3}[/tex]J. Similarly Mai won 4 times as many chips as Kiran ( M = 4K ) and Tyler won half as many chips as Mai ( T = [tex]\frac{1}{2}[/tex]M ). Tyler won half as many chips as Mai, but Mai already won 4 times as many chips as Kiran, who in turn won 2 / 3rd as many chips as Jada. Therefore we can substitute each of the expression into one another,

K = [tex]\frac{2}{3}[/tex]J ⇒ M = 4K ⇒ T = [tex]\frac{1}{2}[/tex]M,

M = 4( [tex]\frac{2}{3}[/tex]J ) ⇒ T = [tex]\frac{1}{2}[/tex]M,

T = [tex]\frac{1}{2}[/tex]( 4 )( [tex]\frac{2}{3}[/tex]J ) - this is our expression.

2 ) If Jada won 42 chips, we can calculate the number of chips everyone has, knowing that they each are related by a common expression,

Kiran = [tex]\frac{2}{3}[/tex]J = [tex]\frac{2}{3}[/tex]( 42 ) = 28 chips,

Mai = 4( [tex]\frac{2}{3}[/tex]J ) = 4( 28 ) = 112 chips,

Tyler = [tex]\frac{1}{2}[/tex]M = [tex]\frac{1}{2}[/tex]( 112 ) = 56 chips

{ Kiran ⇒ 28 chips, Mai ⇒ 112 chips, Tyler ⇒ 56 chips }