Answer:
11[tex]\sqrt{x6/4[/tex]
Given:
The triangle on the left ( triangle 1) has a 60º, a 90º, and a side that equals 11.
So we know the triangle on the right (triangle 2) has a 45º and a 90º angle.
Triangle 2
Since triangle angles always have a sum of 180º, we can solve for the third angle of triangle 2. 180 - (45 + 90) = 45. So the third angle of triangle 2 is 45º.
This is a special type of right triangle called a 45-45-90. An image of the leg/hypotenuse is uploaded below. Meaning, if we solve for the leg that joins the two triangles, we can solve for the hypotenuse.
Triangle 1
To solve for the middle leg, we work with the information we have. So first, find the third angle. 190 - (60 + 90) = 30. This brings us to a second type of special right triangle. An image of the leg/hypotenuse is uploaded below.
Given that we have a side angle of 11, we know that is 2x due to orientation. So 2x=11 simplifies to x=5.5. We then plug that back in to find the leg that we want: 5.5[tex]\sqrt{3}[/tex] .
Triangle 2
Now that we have a side length for the second triangle we can solve. x for this triangle is 5.5[tex]\sqrt{3}[/tex] so to find the hypotenuse we plug into x[tex]\sqrt{2}[/tex]. This turns into (5.5[tex]\sqrt{3}[/tex][tex]\sqrt{2}[/tex]) which simplifies into 5.5[tex]\sqrt{6}[/tex] = 13.47
Answers
The answers are not in the correct form. By going through and finding the decimal form of each, you find out that 11[tex]\sqrt{6/4}[/tex] is equivalent to 13.47, therefore your answer.
