candacesherrin100
candacesherrin100 candacesherrin100
  • 30-07-2020
  • Mathematics
contestada

In the figure below, B is the center of the circle, NL
32, OS = 3x - 2, RB = 26, and SB = 26. Find the value of
X.
​

In the figure below B is the center of the circle NL32 OS 3x 2 RB 26 and SB 26 Find the value ofX class=

Respuesta :

matthewyesil matthewyesil
  • 30-07-2020

Answer: x=12

Step-by-step explanation:

OQ is equal to NL since both contain 90 degree angles and are intersected by a radius. Since OS is 3x-2 and NL is 32, then we need to find OQ and set it equal to NL. OS is half of OQ, so multiplying OS by 2 will get you OQ. 6x-4=32

That yields x=12.

Answer Link
help72955
help72955 help72955
  • 30-07-2020

Answer:

X=12

Step-by-step explanation:

Answer Link

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