Question

In a sample population of people, 36% have the recessive trait of "free" earlobes (q2). What is the frequency of the dominant allele for attached earlobes, p?
a. 0.40
b. 0.64
c. 0.10
d. 0.24

Answer 1

Answer:

Explanation

Given that 36% are recessive in traits

100-36 = 64% for dominant traits considering a whole population to be 100%

P=dominant allele

q= recessive allele

P2= dominant genotype

q2= recessive genotype

according to hardyweinberg principle, p+q=1

64/100= 0.64 frequency for dominant traits or genotype, therefore

p2=0.64

then

P=√0.64

p= 0.8

Therefore, dominant allele frequency (p) for the population is 0.8

Answer 2

Option B is correct. The frequency of the dominant allele  for attached earlobes, p is 0.64

• Let the recessive trait of "free" earlobes be q2

• Let the dominant allele for attached earlobes be "p2"

Hence p + q2 = 1 according to hardyweinberg principle

Given the following parameters:

population of those with recessive traits = 36% = 0.36

p = 1 - q2

p = 1- 0.36

p = 0.64

Hence the frequency of the dominant allele is 0.64

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