Question

In the circle below, QS is a diameter. Suppose m QR = 68° and m<QRT= 56°. Find the following.
​

Answer 1

Answer:

$\boxed{\angle RQS = 56 \ degrees}$

$\boxed{\angle SRT = 56 \ degrees}$

Step-by-step explanation:

A) ∠QRS = 90 degrees (The angle of the triangle opposite to the diameter is always 90)

Given that QR = 68 degrees

So,

∠RSQ = $\frac{1}{2} (QR)$

∠RSQ = 68/2

∠RSQ = 34 degrees

Now, Finding ∠RQS

∠RQS = 180-90-34

∠RQS = 56 degrees

B) ∠SRT = ∠QRS - ∠QRT

=> ∠QRS = 90 (Mentioned above) , ∠QRT = 56 (Given)

So,

∠SRT = 90-56

∠SRT = 34 degrees