Question

WILL MARK AS BRAINLIEST..... A constant force vector f =2i cap+3j cap-5k cap acts on a particle and displaces it from (1,2,-3) m to (2,5,-1) m. find the work done by the force . Plzzzzzzzz helppppppppp !!!!!!!!!

Answer 1

Answer:

W = 1 J

Explanation:

Given that,

A constant force, $F=2i+3j-5k$

The particle displaces it from (1,2,-3) m to (2,5,-1) m. We need to find the work done by the force.  

The position vector from (1,2,-3) m to (2,5,-1) m is (2-1, 5-2, -1-(-3)) i.e. (1, 3, 2) m

Work done is given by :

$W=F{\cdot} d\\\\W=(2i+3j-5k){\cdot} (i+3j+2k)$

From dot product, i.i = j.j = k.k = 1

So,

$W=2+3\times 3-5\times 2\\\\W=1\ J$

So, the work done by the force is 1 J.