Question

what is the factorization of 2x^2+28+98

Answer 1

Answer:

$2(x^2+63)$

Step 1:

To solve this, we have to add the terms without any variables together.

$2x^2+28+98\\2x^2+126$

Step 2:

To factor this, we have to find the multiples of 2x^2 and 126.

$2x^2 = 2x, x\\126 = 63, 2$

Now, we can factor these numbers like this:

$2(x^2+63)$

When we multiply the numbers, we get 2x^2 + 126, and when we separate 126, we get our original question, so that means our factoring is correct.