Question

A mega-pack of markers contains red markers, black markers, and blue markers. There are 24 red markers in the pack. The probability of randomly choosing a red marker is 1 in 3. If the probability of randomly choosing a blue marker is 1 in 8, how many blue markers are in the pack?

Will mark brainlist

Answer 1

Answer:

Number of blue markers  = 9

Step-by-step explanation:

Given that there are 24 red markers.

Probability of randomly choosing a red marker is 1 in 3.

Probability of an event E is given as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

That means the ratio of red markers to total markers is 1:3.

Here number of favorable cases are 24 i.e. the number of red markers

and Total number of cases are equal to total number of markers.

Let T be the total number of markers.

As per definition of probability:

$\dfrac{1}{3}=\dfrac{24}{T}\\\Rightarrow \bold{T = 72}$

Also, given that the probability of choosing a blue marker is 1 in 8.

Let the number of blue markers be B.

As per definition of probability:

$\dfrac{1}{8}=\dfrac{B}{72}\\\Rightarrow \bold{B = 9}$

Hence, the answer is:

Number of blue markers  = 9