Answer:
a) 50 rad/s
b) 39.8 rev
Explanation:
Given:
r = 0.36 m
v₀ = 0 m/s
a = 1.8 m/s
t = 10 s
a) Find: ω
v = at + v₀
v = (1.8 m/s) (10 s) + (0 m/s)
v = 18 m/s
ω = (18 m/s) / (0.36 m)
ω = 50 rad/s
b) Find: Δθ
Δx = v₀ t + ½ at²
Δx = (0 m/s) (10 s) + ½ (1.8 m/s) (10 s)²
Δx = 90 m
Δθ = (90 m) / (2π × 0.36 m)
Δθ = 39.8 rev