Answer:
D. [tex] lw = (x + 5)(x - 5) ; 119 ft^2 [/tex]
Step-by-step explanation:
Dimensions of the old square brick patio:
[tex] length (l) = x ft [/tex]
[tex] width (l) = x ft [/tex]
Note: a square has equal side measure
Dimensions of the new patio
[tex] length (l) = (x + 5) ft [/tex] ==> she increased length by 5 ft
[tex] width (l) = (x - 5) ft [/tex] she reduced width by 5 ft
Expression of the length and width of the new patio is: [tex] lw = (x + 5)(x - 5) [/tex]
Area of the new patio:
Dimension of original patio = x by x = 12 ft by 12 ft.
To find area of the new patio, replace x with 12 in the expression, [tex] lw = (x + 5)(x - 5) [/tex] , which gives you the area.
[tex] area = lw = (12 + 5)(12 - 5) [/tex]
[tex] area = (17)(7) [/tex]
[tex] area = 199 ft^2 [/tex]
Answer is D. [tex] lw = (x + 5)(x - 5) ; 119 ft^2 [/tex]