Question

Find the 9th term geometric sequence 1,1/2,1/2^2

Answer 1

Answer:   $t_9=\dfrac{1}{2^8}$

Step-by-step explanation:

$t_n=t_1\times r^{n-1}\\\\Given: t_1=1,\quad r=\dfrac{1}{2}\\\\\\t_9=1\times\bigg(\dfrac{1}{2}\bigg)^{9-1}\\\\\\.\quad =\large\boxed{\dfrac{1}{2^8}}$