Question

determine the polynomial equivalent to this expression.
x^2-9/x-3

A. x-3

B. -3x-9

C. x+3

D. x^2+3x​

Answer 1

Answer:

$\dfrac{x^2-9}{x-3}= \Large \boxed{x+3}$

Step-by-step explanation:

Hello,

We need to work a little bit of the expression to see if we can simplify.

Do you remember this formula?

   for any a and b reals, we can write

   $a^2-b^2=(a-b)(a+b)$

We will apply it.

For any x real number different from 3 (as dividing by 0 is not allowed)

$\dfrac{x^2-9}{x-3}=\dfrac{x^2-3^2}{x-3}=\dfrac{(x-3)(x+3)}{x-3}=x+3$

So the winner is C !!

Hope this helps.

Do not hesitate if you need further explanation.

Thank you