Question

Please answer both questions

Answer 1

Answer:

36 and 24

Step-by-step explanation:

Answer 2

Answer:

Part a : 20 units², Part d : 12 units²

Step-by-step explanation:

We are given that the side lengths of each square is 6 units. In this case we can calculate the area of the triangles, subtracting from the area of the outer square, such that we calculate the remaining, area of the shaded region / inscribed square.

Area of Outer Square ( Same in all Cases ) = 6 $*$ 6 = 36 units²,

Area of Common Triangles ( 4 Triangles ) = 1 / 2 $*$ Base $*$ Height = 1 / 2 $*$ 2 $*$ ( 6 - 2 ) = 1 / 2 $*$ 2 $*$ 4 = 4,

4 $*$ 4 = 16 units²

Area of inscribed Square = 36 units² - 16 units² = 20 units²

For this second case the inscribed shape is not a square, but it can be calculated through a similar approach,

Area of Outer Square ( Same in all Cases ) = 6 $*$ 6 = 36 units²,

Area of Common Triangles ( 2 Triangles ) = 1 / 2 $*$ Base $*$ Height = 1 / 2 $*$ 4 $*$ 6 = 2 $*$ 6 = 12,

12 $*$ 2 = 24 units²

Area of inscribed shape = 36 units² - 24 units² = 12 units²