Answer:
[tex]\Large \boxed{\sf \ \ 28 \ \text{ and } \ 62 \ \ }[/tex]
Step-by-step explanation:
Hello, let's note a and b the two numbers.
We can write that
a = 6 + 2b
ab = 1736
So
[tex](6+2b)b=1736\\\\ \text{***Subtract 1736*** } <=> 2b^2+6b-1736=0\\\\ \text{***Divide by 2 } <=> b^2+3b-868=0 \\ \\ \text{***factorize*** } <=> b^2 +31b-28b-868=0 \\ \\ <=> b(b+31) -28(b+31)=0 \\ \\ <=> (b+31)(b-28) =0 \\ \\ <=> b = 28 \ \ or \ \ b = -31[/tex]
We are looking for positive numbers so the solution is b = 28
and then a = 6 +2*28 = 62
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
