Answer:
[tex]f(-1) = 3[/tex]
[tex]f(2) = 6[/tex]
[tex]f(12) = 41[/tex]
Step-by-step explanation:
Given
The piece wise function can be split to:-
[tex]f(x) = -2x[/tex] [tex]x\leq -10[/tex]
[tex]f(x) = x + 4[/tex] [tex]-10<x\leq 2[/tex]
[tex]f(x) = 4x - 7[/tex] [tex]x> 2[/tex]
Required
f(-1), f(2) and f(12)
To solve for each of these functions, we first check the range they fall into, then we execute the corresponding function
Solving f(-1)
-1 is within the range of [tex]-10<x\leq 2[/tex]
Hence; we make use of [tex]f(x) = x + 4[/tex]
Substitute -1 for x
[tex]f(-1) = -1 + 4[/tex]
[tex]f(-1) = 3[/tex]
Solving f(2)
2 is within the range of [tex]-10<x\leq 2[/tex]
Hence; we make use of [tex]f(x) = x + 4[/tex]
Substitute 2 for x
[tex]f(2) = 2 + 4[/tex]
[tex]f(2) = 6[/tex]
Solving f(12)
12 is within the range of [tex]x> 2[/tex]
Hence; we make use of [tex]f(x) = 4x - 7[/tex]
Substitute 12 for x
[tex]f(12) = 4(12) - 7[/tex]
[tex]f(12) = 48 - 7[/tex]
[tex]f(12) = 41[/tex]