- 2x
f(x)= x +4,
4x - 7
XS-10
- 10 X2
20. Use the piecewise function to evaluate points f(-1), f(2), and f(12).
O A. f(-1) = 3, f(2) = 1, and f(12) = 41
B. f(-1) = 3, f(2) = 6, and f(12) = 41
O C. f(-1) = 2. f(2) = 1, and |(12) = 41
D. f(-1) = 2. f(2) = 6, and f(12) = 41

2x fx x 4 4x 7 XS10 10 X2 20 Use the piecewise function to evaluate points f1 f2 and f12 O A f1 3 f2 1 and f12 41 B f1 3 f2 6 and f12 41 O C f1 2 f2 1 and 12 4 class=

Respuesta :

Answer:

[tex]f(-1) = 3[/tex]

[tex]f(2) = 6[/tex]

[tex]f(12) = 41[/tex]

Step-by-step explanation:

Given

The piece wise function can be split to:-

[tex]f(x) = -2x[/tex]   [tex]x\leq -10[/tex]

[tex]f(x) = x + 4[/tex]   [tex]-10<x\leq 2[/tex]

[tex]f(x) = 4x - 7[/tex]   [tex]x> 2[/tex]

Required

f(-1), f(2) and f(12)

To solve for each of these functions, we first check the range they fall into, then we execute the corresponding function

Solving f(-1)

-1 is within the range of [tex]-10<x\leq 2[/tex]

Hence; we make use of [tex]f(x) = x + 4[/tex]  

Substitute -1 for x

[tex]f(-1) = -1 + 4[/tex]

[tex]f(-1) = 3[/tex]

Solving f(2)

2 is within the range of [tex]-10<x\leq 2[/tex]

Hence; we make use of [tex]f(x) = x + 4[/tex]  

Substitute 2 for x

[tex]f(2) = 2 + 4[/tex]

[tex]f(2) = 6[/tex]

 

Solving f(12)

12 is within the range of [tex]x> 2[/tex]

Hence; we make use of [tex]f(x) = 4x - 7[/tex]  

Substitute 12 for x

[tex]f(12) = 4(12) - 7[/tex]  

[tex]f(12) = 48 - 7[/tex]

[tex]f(12) = 41[/tex]

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