The nonreflective coating on a camera lens with an index of refraction of 1.21 is designed to minimize the reflection of 570-nm light. If the lens glass has an index of refraction of 1.52, what is the minimum thickness of the coating that will accomplish this ta

Respuesta :

Answer: 117.8 nm

Explanation:

Given,

Nonreflective coating refractive index : n = 1.21

Index of refraction: [tex]n_0[/tex] = 1.52

Wave length of light = λ = 570 nm = [tex]570\times10^{-9}\ m[/tex]

[tex]\text{ Thickness}=\dfrac{\lambda}{4n}[/tex]

[tex]=\dfrac{570\times10^{-9}\ m}{4\times1.21}\\\\\approx\dfrac{117.8\times 10^{-9}\ m}{1}\\\\=117.8\text{ nm}[/tex]

Hence, the minimum thickness of the coating that will accomplish= 117.8 nm

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