Question

You release a pendulum of mass 1 kg from a height of 0.75 m. If there is no air resistance, how fast is the pendulum going when it reaches the bottom

Answer 1

Explanation:

PE = KE

mgh = ½ mv²

v = √(2gh)

v = √(2 × 9.8 m/s² × 0.75 m)

v = 3.83 m/s