simplify each expression using the proper order of operations. please help thank you so much :)

[tex]\frac{41 - 3^2}{\sqrt{36}* 3 - 26 }[/tex]= ?

12 + [tex]{3} \sqrt{8}[/tex]*(9-2)= ?

[tex]\frac{28-(7^2+3)}{-13+3*5}[/tex]= ?

[tex]\frac{28}{4}[/tex] -[tex]\sqrt[3]{8}[/tex]* [tex]\frac{2}{3}[/tex]= ?

7^2 - 5* 8+1= ?

(2* [tex]\sqrt{16}[/tex]) -([tex]\sqrt[3]{27}[/tex]* [tex]\sqrt{81}[/tex]) + 7= ?

Respuesta :

Answer:

[tex]\frac{41 - 3^2}{\sqrt{36} * 3 - 26} = -4[/tex]

[tex]12 + 3\sqrt{8} * (9 - 2) = 12 + 42 \sqrt{2}[/tex]

[tex]\frac{28 - (7^2 + 3)}{-13 + 3 * 5} = -12[/tex]

[tex]7^2 - 5* 8+1 = 10[/tex]

[tex](2 * \sqrt{16}) - (\sqrt[3]{27} * \sqrt{81}) + 1 = -18[/tex]

Step-by-step explanation:

Required: Solve the expressions using proper operation order

To solve this, we'll make use of BODMAS

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[tex]\frac{41 - 3^2}{\sqrt{36} * 3 - 26}[/tex]

Evaluate all squares and square roots

[tex]\frac{41 - 3*3}{\sqrt{36} * 3 - 26}[/tex]

[tex]\frac{41 - 3*3}{6 * 3 - 26}[/tex]

Evaluate the numerator (Start by multiplying 3 * 3)

[tex]\frac{41 - 9}{6 * 3 - 26}[/tex]

Subtract 9 from 41

[tex]\frac{32}{6 * 3 - 26}[/tex]

Evaluate the denominator (Start by multiplying 6 * 3)

[tex]\frac{32}{18 - 26}[/tex]

[tex]\frac{32}{-8}[/tex]

Divide 32 by -8

-4

Hence;

[tex]\frac{41 - 3^2}{\sqrt{36} * 3 - 26} = -4[/tex]

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[tex]12 + 3\sqrt{8} * (9 - 2)[/tex]

Start by evaluating the bracket

[tex]12 + 3\sqrt{8} * 7[/tex]

Then evaluate the multiplication

[tex]12 + 21\sqrt{8}[/tex]

Simplify the square root

[tex]12 + 21\sqrt{4 * 2}[/tex]

Split the square root

[tex]12 + 21\sqrt{4} * \sqrt{2}[/tex]

Take Square root of 4

[tex]12 + 21 * 2} * \sqrt{2}[/tex]

[tex]12 + 42 \sqrt{2}[/tex]

Hence;

[tex]12 + 3\sqrt{8} * (9 - 2) = 12 + 42 \sqrt{2}[/tex]

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[tex]\frac{28 - (7^2 + 3)}{-13 + 3 * 5}[/tex]

Evaluate 7²

[tex]\frac{28 - (49 + 3)}{-13 + 3 * 5}[/tex]

Evaluate all expression in the bracket

[tex]\frac{28 - (52)}{-13 + 3 * 5}[/tex]

[tex]\frac{28 - 52}{-13 + 3 * 5}[/tex]

Evaluate 3 * 5

[tex]\frac{28 - 52}{-13 + 1 5}[/tex]

[tex]\frac{-2 4}{2}[/tex]

[tex]-12[/tex]

Hence;

[tex]\frac{28 - (7^2 + 3)}{-13 + 3 * 5} = -12[/tex]

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[tex]7^2 - 5* 8+1[/tex]

Evaluate 7²

[tex]49 - 5* 8+1[/tex]

Evaluate 5 * 8

[tex]49 - 40 + 1[/tex]

[tex]10[/tex]

[tex]7^2 - 5* 8+1 = 10[/tex]

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[tex](2 * \sqrt{16}) - (\sqrt[3]{27} * \sqrt{81}) + 1[/tex]

Evaluate all square root and cube root

[tex](2 * 4) - (3 * 9) + 1[/tex]

Solve the expressions in bracket

[tex]8 - 27 + 1[/tex]

[tex]-18[/tex]

Hence;

[tex](2 * \sqrt{16}) - (\sqrt[3]{27} * \sqrt{81}) + 1 = -18[/tex]

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